Merge pull request #1244 from black-puppydog/cow-rework

refactor(cow1):  replace main with tests
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liv 2023-02-15 14:16:22 +01:00 committed by GitHub
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2 changed files with 49 additions and 23 deletions

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@ -4,6 +4,9 @@
// Cow is a clone-on-write smart pointer. // Cow is a clone-on-write smart pointer.
// It can enclose and provide immutable access to borrowed data, and clone the data lazily when mutation or ownership is required. // It can enclose and provide immutable access to borrowed data, and clone the data lazily when mutation or ownership is required.
// The type is designed to work with general borrowed data via the Borrow trait. // The type is designed to work with general borrowed data via the Borrow trait.
//
// This exercise is meant to show you what to expect when passing data to Cow.
// Fix the unit tests by checking for Cow::Owned(_) and Cow::Borrowed(_) at the TODO markers.
// I AM NOT DONE // I AM NOT DONE
@ -20,29 +23,52 @@ fn abs_all<'a, 'b>(input: &'a mut Cow<'b, [i32]>) -> &'a mut Cow<'b, [i32]> {
input input
} }
fn main() { #[cfg(test)]
// No clone occurs because `input` doesn't need to be mutated. mod tests {
let slice = [0, 1, 2]; use super::*;
let mut input = Cow::from(&slice[..]);
match abs_all(&mut input) { #[test]
Cow::Borrowed(_) => println!("I borrowed the slice!"), fn reference_mutation() -> Result<(), &'static str> {
_ => panic!("expected borrowed value"), // Clone occurs because `input` needs to be mutated.
let slice = [-1, 0, 1];
let mut input = Cow::from(&slice[..]);
match abs_all(&mut input) {
Cow::Owned(_) => Ok(()),
_ => Err("Expected owned value"),
}
} }
// Clone occurs because `input` needs to be mutated. #[test]
let slice = [-1, 0, 1]; fn reference_no_mutation() -> Result<(), &'static str> {
let mut input = Cow::from(&slice[..]); // No clone occurs because `input` doesn't need to be mutated.
match abs_all(&mut input) { let slice = [0, 1, 2];
Cow::Owned(_) => println!("I modified the slice and now own it!"), let mut input = Cow::from(&slice[..]);
_ => panic!("expected owned value"), match abs_all(&mut input) {
// TODO
}
} }
// No clone occurs because `input` is already owned. #[test]
let slice = vec![-1, 0, 1]; fn owned_no_mutation() -> Result<(), &'static str> {
let mut input = Cow::from(slice); // We can also pass `slice` without `&` so Cow owns it directly.
match abs_all(&mut input) { // In this case no mutation occurs and thus also no clone,
// TODO // but the result is still owned because it always was.
Cow::Borrowed(_) => println!("I own this slice!"), let slice = vec![0, 1, 2];
_ => panic!("expected borrowed value"), let mut input = Cow::from(slice);
match abs_all(&mut input) {
// TODO
}
}
#[test]
fn owned_mutation() -> Result<(), &'static str> {
// Of course this is also the case if a mutation does occur.
// In this case the call to `to_mut()` returns a reference to
// the same data as before.
let slice = vec![-1, 0, 1];
let mut input = Cow::from(slice);
match abs_all(&mut input) {
// TODO
}
} }
} }

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@ -1010,11 +1010,11 @@ https://doc.rust-lang.org/stable/book/ch16-00-concurrency.html
[[exercises]] [[exercises]]
name = "cow1" name = "cow1"
path = "exercises/smart_pointers/cow1.rs" path = "exercises/smart_pointers/cow1.rs"
mode = "compile" mode = "test"
hint = """ hint = """
Since the vector is already owned, the `Cow` type doesn't need to clone it. If Cow already owns the data it doesn't need to clone it when to_mut() is called.
Checkout https://doc.rust-lang.org/std/borrow/enum.Cow.html for documentation Check out https://doc.rust-lang.org/std/borrow/enum.Cow.html for documentation
on the `Cow` type. on the `Cow` type.
""" """