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feat(move_semantics2): rewrite hint

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liv 2023-06-12 12:07:18 +02:00
parent 1ce9d93e94
commit 369ae2e63d
2 changed files with 19 additions and 20 deletions
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10
exercises/move_semantics/move_semantics2.rs
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@ -2,23 +2,21 @@
// Execute `rustlings hint move_semantics2` or use the `hint` watch subcommand for a hint. // Execute `rustlings hint move_semantics2` or use the `hint` watch subcommand for a hint.
// Expected output: // Expected output:
// vec0 has length 3 content `[22, 44, 66]` // vec0 has length 3, with contents `[22, 44, 66]`
// vec1 has length 4 content `[22, 44, 66, 88]` // vec1 has length 4, with contents `[22, 44, 66, 88]`
// I AM NOT DONE // I AM NOT DONE
fn main() { fn main() {
let vec0 = Vec::new(); let vec0 = Vec::new();
// Do not move the following line!
let mut vec1 = fill_vec(vec0); let mut vec1 = fill_vec(vec0);
// Do not change the following line! println!("{} has length {}, with contents: `{:?}`", "vec0", vec0.len(), vec0);
println!("{} has length {} content `{:?}`", "vec0", vec0.len(), vec0);
vec1.push(88); vec1.push(88);
println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1); println!("{} has length {}, with contents `{:?}`", "vec1", vec1.len(), vec1);
} }
fn fill_vec(vec: Vec<i32>) -> Vec<i32> { fn fill_vec(vec: Vec<i32>) -> Vec<i32> {

29
info.toml
View file

@ -287,23 +287,24 @@ Also: Try accessing `vec0` after having called `fill_vec()`. See what happens!""
[[exercises]] [[exercises]]
name = "move_semantics2" name = "move_semantics2"
path = "exercises/move_semantics/move_semantics2.rs" path = "exercises/move_semantics/move_semantics2.rs"
mode = "compile" mode = "test"
hint = """ hint = """
So, `vec0` is passed into the `fill_vec` function as an argument. In Rust, When running this exercise for the first time, you'll notice an error about
when an argument is passed to a function and it's not explicitly returned, "borrow of moved value". In Rust, when an argument is passed to a function and
you can't use the original variable anymore. We call this "moving" a variable. it's not explicitly returned, you can't use the original variable anymore.
Variables that are moved into a function (or block scope) and aren't explicitly We call this "moving" a variable. When we pass `vec0` into `fill_vec`, it's being
returned get "dropped" at the end of that function. This is also what happens here. "moved" into `vec1`, meaning we can't access `vec0` anymore after the fact.
There's a few ways to fix this, try them all if you want: Rust provides a couple of different ways to mitigate this issue, feel free to try them all:
1. Make another, separate version of the data that's in `vec0` and pass that 1. You could make another, separate version of the data that's in `vec0` and pass that
to `fill_vec` instead. to `fill_vec` instead.
2. Make `fill_vec` borrow its argument instead of taking ownership of it, 2. Make `fill_vec` borrow its argument instead of taking ownership of it,
and then copy the data within the function in order to return an owned and then copy the data within the function (`vec.clone()`) in order to return an owned
`Vec<i32>` `Vec<i32>`.
3. Make `fill_vec` *mutably* borrow a reference to its argument (which will need to be 3. Or, you could make `fill_vec` *mutably* borrow a reference to its argument (which will need to be
mutable), modify it directly, then not return anything. Then you can get rid mutable), modify it directly, then not return anything. This means that `vec0` will change over the
of `vec1` entirely -- note that this will change what gets printed by the course of the function, and makes `vec1` redundant (make sure to change the parameters of the `println!`
first `println!`""" statements if you go this route)
"""
[[exercises]] [[exercises]]
name = "move_semantics3" name = "move_semantics3"