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@ -42,6 +42,6 @@ fn square(num: i32) -> i32 {
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// It happens because Rust distinguishes between expressions and statements: expressions return
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// a value based on its operand, and statements simply return a () type which behaves just like `void` in C/C++ language.
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// We want to return a value of `i32` type from the `square` function, but it is returning a `()` type...
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// They are not the same. There are two solusions:
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// They are not the same. There are two solutions:
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// 1. Add a `return` ahead of `num * num;`
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// 2. remove `;`, make it to be `num * num`
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