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Simplify next_pending_exercise_ind

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This commit is contained in:
mo8it 2024-08-29 01:59:04 +02:00
parent fc1f9f0124
commit fd2bf9f6f6
1 changed files with 16 additions and 19 deletions
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29
src/app_state.rs
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@ -313,25 +313,22 @@ impl AppState {
// Return the index of the next pending exercise or `None` if all exercises are done.
fn next_pending_exercise_ind(&self) -> Option<usize> {
if self.current_exercise_ind + 1 == self.exercises.len() {
// The last exercise is done.
// Search for exercises not done from the start.
return self.exercises[..self.current_exercise_ind]
.iter()
.position(|exercise| !exercise.done);
}
// The done exercise isn't the last one.
// Search for a pending exercise after the current one and then from the start.
match self.exercises[self.current_exercise_ind + 1..]
let next_ind = self.current_exercise_ind + 1;
self.exercises
// If the exercise done isn't the last, search for pending exercises after it.
.get(next_ind..)
.and_then(|later_exercises| {
later_exercises
.iter()
.position(|exercise| !exercise.done)
{
Some(ind) => Some(self.current_exercise_ind + 1 + ind),
None => self.exercises[..self.current_exercise_ind]
.map(|ind| next_ind + ind)
})
// Search from the start.
.or_else(|| {
self.exercises[..self.current_exercise_ind]
.iter()
.position(|exercise| !exercise.done),
}
.position(|exercise| !exercise.done)
})
}
/// Official exercises: Dump the solution file form the binary and return its path.